3(x+1)+x^2=x^2+12

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Solution for 3(x+1)+x^2=x^2+12 equation:


Simplifying
3(x + 1) + x2 = x2 + 12

Reorder the terms:
3(1 + x) + x2 = x2 + 12
(1 * 3 + x * 3) + x2 = x2 + 12
(3 + 3x) + x2 = x2 + 12

Reorder the terms:
3 + 3x + x2 = 12 + x2

Add '-1x2' to each side of the equation.
3 + 3x + x2 + -1x2 = 12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 3x + 0 = 12 + x2 + -1x2
3 + 3x = 12 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3 + 3x = 12 + 0
3 + 3x = 12

Solving
3 + 3x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 3x = 12 + -3

Combine like terms: 3 + -3 = 0
0 + 3x = 12 + -3
3x = 12 + -3

Combine like terms: 12 + -3 = 9
3x = 9

Divide each side by '3'.
x = 3

Simplifying
x = 3

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